2z-3-2[1+z]=-5

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Solution for 2z-3-2[1+z]=-5 equation:


Simplifying
2z + -3 + -2[1 + z] = -5
2z + -3 + [1 * -2 + z * -2] = -5
2z + -3 + [-2 + -2z] = -5

Reorder the terms:
-3 + -2 + 2z + -2z = -5

Combine like terms: -3 + -2 = -5
-5 + 2z + -2z = -5

Combine like terms: 2z + -2z = 0
-5 + 0 = -5
-5 = -5

Add '5' to each side of the equation.
-5 + 5 = -5 + 5

Combine like terms: -5 + 5 = 0
0 = -5 + 5

Combine like terms: -5 + 5 = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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